vernarim wrote:
@lygra:I never would have hurt you!...I really apologize if you feel that!
I was only asking you in which way did you measured/show a good shaped 3.5M square wave, nothing all.
Could you post any DSO snapshot of that wave?
I survived Vietnam so I am sure that you can not hurt me emotionally or physically, I just don't want valid facts to be discredited. Although against better judgment, I will do one or two more responses on this matter if you will limit yourself to provable facts and the 3.5xxMhz display as the point of discussion. I no longer have a DSO Quad because my engineering hardware v2.2 was returned to China for exchange for a v2.6 model and that is the only reason you have not seen a picture here already. When I made those measurements for the benefit of those needing more info (before the betas were available), pictures were not included because the engineering model firmware has trigger, capture, and measurement issues that need to be addressed, and those fixes would most likely change the screen displays. I was just providing the bare facts at that time.
vernarim wrote:
I have explained what in the lab I have tried, which instrumentation and how much was the amplitude of the signals. I guess anyone can test it with a quite common scope with 100-200MHz of BW. The wave I have seen (under several context) is far from being square. The picture you have attached is partially correct.
Which part of my previous attachment is incorrect? Be specific and don't generalize because that serves no purpose. All square waves have some rise-time (both the generator and the display) due to the lack of infinite odd harmonics, and that is not shown for simplicity.
vernarim wrote:
It is true that having a perfect signal in the ADC input (better: the track-and-hold input) the equivalent wave will be distorted. It is also true that never we could sample a signal having a BW over fs/2, because it generates aliasing. That is a fundamental math rule of discrete signals (Shannon). That mean we cannot feed any signal higher than 36MHz (theoretically speaking), let's say 10-20MHz practically. Otherwise the equivalent sampled signal would be a mess, without any chance to reconstruct correctly. This is clear represented by the frequency spectrum that would see the baseband and the lower-modulated band overlapped.
These parameters are not relative to a 3.5xxMhz square wave being viewed on the DSO Quad with SYS v1.30 or earlier.
vernarim wrote:
When I write "signal" here, I mean SINE waves, not square or else. You know that the only "pure" signal is just a sine wave. Any other periodic signal can be thought as composition of harmonics. In the case, a (perfect) square wave is one of the most "tedious", because it has only odd harmonics, decaying hyperbolically (so really slowly).
For example, let's consider a 1MHz perfect square wave. The main sine wave is at 1MHz, of course, and it is the greater in amplitude. It has a 3rd harmonic, whose amplitude is about 1/3 the main. Then there is the 5th, having 1/5 of amplitude, etc.
These parameters are not relative to a 3.5xxMhz square wave being viewed on the DSO Quad with SYS v1.30 or earlier.
vernarim wrote:
If the scope would had a 15MHz of BW (as HugeMan is going to do), then I would have attenuations over the 13-15th harmonic...my wave would be a good square anyway. Since I do NOT see that and I see a oddly shaped wave, I'd suppose the BW is much slower.
When you replace your word "slower" with the word "narrower", then we are approaching the crux of this misunderstanding. What is your T/Div setting when you conducted this measurement? If you don't remember, then repeat your measurements and tell me what you used for T/Div for the same results.
vernarim wrote:
How to prove it? Well, simple...that was a typical high-school task. Just feed the DSO with a 1MHz (or less) sine: no matter what's the amplitude. On the DSO display I see a good-shaped sine having about 500mVpp.
How is defined the BW? The cut-off frequency is defined as the point where the amplitude falls to 1/sqrt(2)=0.707 the nominal. That's good...so step up the input frequency to 2MHz: how is the sine on the DSO display?...It is still a good-shaped sine, but it's amplitude is about 75% as before. That is: the BW of the analog section of the DSO is 2-3MHz.
Unfortunately you are now talking about analog display roll-off and not band-pass roll-off. This is probably where your misunderstanding takes place. You have also switched off topic to a sine wave at a different frequency. BenF has already cited the artifact of display amplitude roll-off due to sampling rate choices. This display roll-off may be negatively influencing your viewed results. I did not compare the amplitude of the square wave at different frequencies such as 1.88Mhz like you are doing so we are now mixing apples and oranges again. Refer to page-5, my second post and BenF's following response at
viewtopic.php?f=12&t=1793&start=40 for more details about display roll-off.
vernarim wrote:
Hope that was clear enough.
It wont be clear enough until you place a 3.5xxMhz square wave signal into the DSO Quad and use the faster T/Div settings to view the signal with both analog channels active, and then tell me what you see. Then we will both be on the same page. Sorry about being short and direct with you, but we have to discuss the same issues in order to communicate successfully.