SKU
110990063
$79.00
Hardware/software platform for creating cubic-inch sensor peripherals for the mobile phone Enables a new class of small and cheap phone-centric sensor peripherals Be tested with the iPhone 3G/3GS/4G, iPod Touch, and iPad devices

Please note before purchase that this product doesn't have tech support. Sorry for the inconveniences.

HiJack is a hardware/software platform for creating cubic-inch sensor peripherals for the mobile phone. HiJack devices harvest power and use bandwidth from the mobile phone's headset interface. The HiJack platform enables a new class of small and cheap phone-centric sensor peripherals that support plug-and-play operation. HiJack has been tested with the iPhone 3G/3GS/4G, iPod Touch, and iPad devices.

Pack list:

  • Hijack board X1

  • Programmer X1

  • Protoboard X2

  • Cable X5


For more information, you can visit its product page, or wiki page.

Or check out the transparent article, HiJack and techBASIC “Hello world! Project, from Mike Westfield.

Technical details

Dimensions 0mm x0mm x0mm
Weight G.W 70g
Battery Exclude

ECCN/HTS

HSCODE 9023009000
ROHS 1
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Product Faqs


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  • Question by: admin on 2018-12-18 02:38:40

    Hi, Mario.I'm sorry that i don't really understand how you can use RTC with two Arduinos together simultaneously.

    Answer by: admin on 2018-12-18 02:38:40
  • Question by: admin on 2018-12-18 02:38:39

    You can probably use CCS, but you will have to write the firmware from scratch. The current firmware was written in NesC and uses TinyOS. It is fairly easy to install a TinyOS development environment on a linux machine, plus it is open source. The foll

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    But,now is July.

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    Thanks for your attention, but it is not convenient to sell it overseas. Maybe you can find another battery to instead of it.

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    You can add some codes:clock.getTime();if(clock.hour_12) { clock.hour=clock.hour-12; }

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    Thanks; grounding the battery + terminal solved my problem. I was really confused because it worked fine two days ago. I guess it just doesn't like having the battery + floating.

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    Hi Sebastian Saez.Sorry for that,i have checked and updated it again.Thanks for your attention.

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    Hi.If your battery is right,and the program can be complied without any errors,maybe the code of your own project has a little problem.Could The RTC can work well separately?

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:39

    Hi.When using RTC with a battery,the time will go on.And when power is off,the time will turn to "45:165:85 165/165/165",it's a wrong time.More information about setting,you can refer to the libraries.

    Answer by: admin on 2018-12-18 02:38:39
  • Question by: admin on 2018-12-18 02:38:38

    good news, a grove cable was also included in the package from now .

    Answer by: admin on 2018-12-18 02:38:38
  • Question by: admin on 2018-12-18 02:38:38

    Dear customer, i'm so sorry, we have no plan to import this product temporary.

    Answer by: admin on 2018-12-18 02:38:38
  • Question by: admin on 2018-12-18 02:38:38

    This product will be available soon, you could click NOTIFY ME, we will e-mail you if it back in stock.

    Answer by: admin on 2018-12-18 02:38:38
  • I did the example 1 as the following URL.
    http://www.seeedstudio.com/wik...
    although I fixed the value of twig_Potentiometer, that is, I stopped the

    Question by: admin on 2018-12-18 02:38:38

    Hello Cong Yue , according to our test of hijack, it is work right with itouch and iphone 4 expect iphone 4S. We have no idea why is it. We will try to contact the designer for this issue.

    Answer by: admin on 2018-12-18 02:38:38
  • Question by: admin on 2018-12-18 02:38:38

    Hello , sorry that we don't have idea because we are not the designer , please refer to the official website , or you can directly contact to the designer .Thansk` thomas.schmid@utah.edu

    Answer by: admin on 2018-12-18 02:38:38
  • Question by: admin on 2018-12-18 02:38:38

    Hello, please refer to the wiki page , thanks.

    Answer by: admin on 2018-12-18 02:38:38
  • Question by: admin on 2018-12-18 02:38:38

    Sorry that we haven't more instructions , you can search on the Hijack official website .
    http://web.eecs.umich.edu/~pra...
    Or you can contact the designer , the ema

    Answer by: admin on 2018-12-18 02:38:38
  • q4523452345

    Question by: admin on 2018-12-18 02:38:37

    please note each relay would need about 100mA current when working . so, maybe the arduino can not supply such a large current to support 13 relays.

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    Could you send some pictures? thx

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    I have had the same exact issue. Did you ever figure this out?

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    Hi.You can drop line to order@seeedstudio.com.They can help you solve problems of purchase.

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    In fact, we don't need to know the value of R16, it's should be better for us get a ratio and omit R16 in two formulas. More information please refer to the modified wiki.

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    Nevermind, figured it out. Heater power is 0.9V @ 120 mA which is 108 mW. Arduino can supply 200 mW per pin.

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:37

    Hi,Yan,you can scan and refer to the wiki:http://www.seeedstudio.com/wik... ----it would be useful for you.enjoy~

    Answer by: admin on 2018-12-18 02:38:37
  • Question by: admin on 2018-12-18 02:38:36

    The problem was solved by using Photocoupler. Now the noise from the relay were separated. Recommend you to place it in the circuit (for example C1010 - High Reliability Photocoupler - COSMO Electronics Corporation)

    Answer by: admin on 2018-12-18 02:38:36
  • Question by: admin on 2018-12-18 02:38:36

    Hi, i do not hear any sound from the relay as it is normal when the circuit is open/closed, and i think that my code is ok since i can see the led being turned on and then turned of when i close/open the circuit. Here is the class i have programmed for

    Answer by: admin on 2018-12-18 02:38:36